(OS1-1) Simple Pendulum
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In simple harmonic motion, the restoring force must be proportional to the:
1
amplitude
2
frequency
3
velocity
4
displacement
5
displacement squared
An oscillatory motion must be simple harmonic if:
1
the amplitude is small
2
the potential energy is equal to the kinetic energy
3
the motion is along the arc of a circle
4
the acceleration varies sinusoidally with time
5
the derivative, dU/dx, of the potential energy is negative
In simple harmonic motion, the magnitude of the acceleration is:
1
constant
2
proportional to the displacement
3
inversely proportional to the displacement
4
greatest when the velocity is greatest
5
never greater than g
A particle is in simple harmonic motion with period T. At time t = 0 it is at the equilibrium point. Of the following times, at which time is it furthest from the equilibrium point?
1
0.5T
2
0.7T
3
T
4
1.4T
5
1.5T
A particle moves back and forth along the x axis from x = −xm to x = +xm, in simple harmonic motion with period T. At time t = 0 it is at x = +xm. When t = 0.75T:
1
it is at x = 0 and is traveling toward x = +xm
2
it is at x = 0 and is traveling toward x = −xm
3
it at x = +xm and is at rest
4
it is between x = 0 and x = +xm and is traveling toward x = −xm
5
it is between x = 0 and x = −xm and is traveling toward x = −xm
A particle oscillating in simple harmonic motion is:
1
never in equilibrium because it is in motion
2
never in equilibrium because there is always a force
3
in equilibrium at the ends of its path because its velocity is zero there
4
in equilibrium at the center of its path because the acceleration is zero there
5
in equilibrium at the ends of its path because the acceleration is zero there
An object is undergoing simple harmonic motion. Throughout a complete cycle it:
1
has constant speed
2
has varying amplitude
3
has varying period
4
has varying acceleration
5
has varying mass
When a body executes simple harmonic motion, its acceleration at the ends of its path must be:
1
zero
2
less than g
3
more than g
4
suddenly changing in sign
5
none of these
A particle is in simple harmonic motion with period T. At time t = 0 it is halfway between the equilibrium point and an end point of its motion, traveling toward the end point. The next time it is at the same place is:
1
t = T
2
t = T/2
3
t = T/4
4
t = T/8
5
none of the above
A simple pendulum makes 20 complete oscillations in 10 s. Its period is:
1
2Hz
2
10 s
3
0.5Hz
4
2 s
5
0.50 s
A simple pendulum makes 20 vibrations in 10 s. Its frequency is:
1
2Hz
2
10 s
3
0.05 Hz
4
2 s
5
0.50 s
A simple pendulum makes 20 vibrations in 10 s. Its angular frequency is:
1
0.79 rad/s
2
1.57 rad/s
3
2.0 rad/s
4
6.3 rad/s
5
12.6 rad/s
Frequency f and angular frequency ω are related by
1
f = πω
2
f = 2πω
3
f = ω/π
4
f = ω/2π
5
f = 2ω/π
In simple harmonic motion, the magnitude of the acceleration is greatest when:
1
the displacement is zero
2
the displacement is maximum
3
the speed is maximum
4
the force is zero
5
the speed is between zero and its maximum
In simple harmonic motion, the displacement is maximum when the:
1
acceleration is zero
2
velocity is maximum
3
velocity is zero
4
kinetic energy is maximum
5
momentum is maximum
In simple harmonic motion:
1
the acceleration is greatest at the maximum displacement
2
the velocity is greatest at the maximum displacement
3
the period depends on the amplitude
4
the acceleration is constant
5
the acceleration is greatest at zero displacement
If the length of a simple pendulum is doubled, its period will:
1
halve
2
be greater by a factor of √2
3
be less by a factor of √2
4
double
5
remain the same
The period of a simple pendulum is 1 s on Earth. When brought to a planet where g is one-tenth that on Earth, its period becomes:
1
1 s
2
1/√10 s
3
1/10 s
4
√10 s
5
10 s
The amplitude of oscillation of a simple pendulum is increased from 1◦ to 4◦. Its maximum acceleration changes by a factor of:
1
1/4
2
1/2
3
2
4
4
5
16
A simple pendulum of length L and mass M has frequency f. To increase its frequency to 2f:
1
increase its length to 4L
2
increase its length to 2L
3
decrease its length to L/2
4
decrease its length to L/4
5
decrease its mass to < M/4
A simple pendulum consists of a small ball tied to a string and set in oscillation. As the pendulum swings the tension force of the string is:
1
constant
2
a sinusoidal function of time
3
the square of a sinusoidal function of time
4
the reciprocal of a sinusoidal function of time
5
none of the above
A mass M is attached to an ideal massless spring. When this system is set in motion with amplitude A, it has a period T. What is the period if the amplitude of the motion is increased to 2A?
1
2T
2
T/2
3
2T
4
4T
5
T
A mass M is attached to an ideal massless spring. When this system is set in motion, it has a period T. What is the period if the mass is doubled to 2M?
1
3T
2
T/2
3
2T
4
4T
5
T
In simple harmonic motion, the speed is greatest at that point in the cycle when
1
the magnitude of the acceleration is a maximum.
2
the displacement is a maximum.
3
the magnitude of the acceleration is a minimum.
4
the potential energy is a maximum.
5
the kinetic energy is a minimum.
.An object of mass m is attached to string of length L. When it is released from point A, the object oscillates between points A and B. Which statement about the system consisting of the pendulum and the Earth is correct?
1
The gravitational potential energy of the system is greatest at A and B.
2
The kinetic energy of mass m is greatest at point O.
3
The greatest rate of change of momentum occurs at A and B.
4
All of the above are correct.
5
Only (a) and (b) above are correct.
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Result:
Show correct answer
var
h(m)
h²(m²)
√h(m)
t(s)
t²(s²)
√t(s)
Δt(s)
Δt²(s²)
l(m)
N2
N1
Δ√h(m)
h²ₐᵥ(m²)
t²ₐᵥ(m²)
h(m)
h²(m²)
T(s)
v
t²(s²)
√t(s)
Δt(s)
Δt²(s²)
Δ√t
Δh(m)
Δh²(m²)
Δ√h(m)
h²ₐᵥ(m²)
t²ₐᵥ(m²)
h(m)
h²(m²)
V
T(s)
t²(s²)
√t(s)
Δt(s)
Δt²(s²)
Δ√t
Δh(m)
Δh²(m²)
Δ√h(m)
h²ₐᵥ(m²)
t²ₐᵥ(m²)
h(m)
h²(m²)
V
T(s)
t²(s²)
√t(s)
Δt(s)
Δt²(s²)
Δ√t
Δh(m)
Δh²(m²)
Δ√h(m)
h²ₐᵥ(m²)
t²ₐᵥ(m²)
h(m)
h²(m²)
√h(m)
Tₐᵥ
t²(s²)
√t(s)
Δt(s)
Δt²(s²)
Vₐᵥ
Δh(m)
Δh²(m²)
Δ√h(m)
h²ₐᵥ(m²)
t²ₐᵥ(m²)
h(m)
h²(m²)
√h(m)
t(s)
T²(s²)
√t(s)
Δt(s)
Δt²(s²)
Δ√t
ΔV
Δh²(m²)
Δ√h(m)
h²ₐᵥ(m²)
t²ₐᵥ(m²)
h(m)
h²(m²)
√h(m)
ΔT(s)
T²(s²)
√t(s)
Δt(s)
Δt²(s²)
Δ√t
ΔV
Δh²(m²)
Δ√h(m)
h²ₐᵥ(m²)
t²ₐᵥ(m²)
No
OK
Point 1: X =
Y =
slope =
Point 2: X =
Y =
g =
m/s
2
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Draw Best Line
Warning,the angle must be smaller than 10 Degree.
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Please, Make a displacement with angle less than 10 Degree.
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you must make 3 trails only for one length
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